Free study guide · GCSE Foundation & Higher

Simultaneous equations, finally easy

Learn to solve two unknowns with receipts. Use elimination, multiplication, and substitution. Try exam-style questions with answers.

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How can you work out two prices when nobody tells you either one?

Simultaneous equations feel hard because there are two unknowns. Use the café receipts analogy to find the prices. Line up the receipts and subtract to find the difference.

The picture to keep in your head: Two café receipts

Two receipts from the same café: 2 coffees and a cake cost £7, 1 coffee and a cake cost £5. Line them up and the only difference is one extra coffee, which must cost the £2 difference. Subtracting the receipts makes the cake vanish; that is elimination. Multiplying a whole equation is buying the whole order twice: every item and the total double.

The method, every time

  1. Line up the receipts to see what’s different.
  2. Subtract receipts with same signs to remove the same items.
  3. Multiply a receipt to match the number of items in the other.
  4. Add receipts with different signs to cancel out the same items.
  5. Find one price first, then use it to find the other.

Words you'll see

elimination
Subtracting equations to remove one variable.
multiplication
Scaling an equation to match the other.
substitution
Using one equation to find the value of a variable.
unknowns
Variables you need to find, like coffee and cake prices.
receipts
Equations that show how much each item costs together.
1 · Elimination

Same sign? Subtract. Different signs? Add.

Imagine two café receipts. If the same item appears with the same sign in both, subtract them to cancel it out. This is like removing a charge with a refund. If the signs differ, add them to cancel. This rule helps you find the value of one item at a time.

Worked exampleSolve 3x + 2y = 13 and 5x - 2y = 11
3x + 2y = 13 (1)
Label the receipts
5x - 2y = 11 (2)
+2y and -2y: different signs, so add
8x = 24
(1) + (2): the y terms cancel
x = 3
Divide by 8
9 + 2y = 13, so y = 2
Put x = 3 into (1)
5 × 3 - 2 × 2 = 11 ✓
Check in (2)
x = 3, y = 2
answer

Watch out

  • Subtracting a negative wrongly. Remember subtracting a negative is adding the positive
  • Forgetting to subtract the totals. Always subtract the entire equation, not just one term
  • Stopping after finding x. Always find both variables to complete the solution
2 · When nothing matches

Multiply a whole receipt first

Imagine two café receipts. If you want to match the same item, you might need to buy the whole order again. That's multiplying a whole equation. Multiply one or both equations so one letter matches. Multiply every term and the total.

Worked exampleSolve 3x + 2y = 12 and 4x - 5y = -7
3x + 2y = 12 (1)
Nothing matches yet
4x - 5y = -7 (2)
2 and 5 both go into 10
15x + 10y = 60
(1) × 5: every term, the total too
8x - 10y = -14
(2) × 2
23x = 46, so x = 2
Add: the y terms cancel
6 + 2y = 12, so y = 3
Put x = 2 into (1)
x = 2, y = 3
answer

Watch out

  • Multiplying the letters but not the total. Multiply every term in the equation, including the total
  • Choosing the harder letter to match. Choose the letter that makes the math easier
3 · Substitution

When one equation says y = ...

Imagine two receipts from the same café. One says y = 3x - 4, the other says 2x + y = 11. Since y is already known in the first receipt, you can swap it into the second. Like swapping the cake for its price. This is substitution. Just plug the expression for y into the other equation and solve.

Worked exampleSolve y = 3x - 4 and 2x + y = 11
y = 3x - 4
Given equation 1
2x + (3x - 4) = 11
Substitute y = 3x - 4 into equation 2
5x - 4 = 11
Combine like terms
5x = 15
Add 4 to both sides
x = 3
Divide both sides by 5
y = 3(3) - 4
Substitute x = 3 back into equation 1
y = 5
Calculate the value of y
x = 3, y = 5
answer

Watch out

  • Dropping the brackets so the minus is lost. Keep brackets when substituting y
  • Putting x back into the wrong equation. Always substitute x into the original y = 3x - 4
4 · Higher

One straight line, one curve

Imagine two receipts: one has a straight line of items, the other a curved line of items. When a line crosses a curve, they share the same x and y values. To find where they meet, substitute the straight line into the curve. This gives you a quadratic equation. Solve it to find the x-values, then use the straight line to find the matching y-values. The rule is: substitute the straight line into the curve, rearrange to = 0, factorise, and find the x-values, then find the y-values.

Worked exampleSolve y = x + 3 and y = x2 + 1
y = x + 3
Start with the straight line equation.
x + 3 = x2 + 1
Substitute y from the straight line into the curve.
0 = x2 - x - 2
Rearrange to form a quadratic equation.
(x - 2)(x + 1) = 0
Factorise the quadratic equation.
x = 2 or x = -1
Set each factor equal to zero.
y = 2 + 3 = 5
Use the straight line to find y when x = 2.
y = -1 + 3 = 2
Use the straight line to find y when x = -1.
x = 2, y = 5 and x = -1, y = 2
answer

Watch out

  • Giving x values without their y values. Always give x and y values as pairs.
  • Expanding (x + 1)2 as x2 + 1. Expand (x + 1)2 as x2 + 2x + 1.
Practice

23 exam-style simultaneous equations questions

Show your working: most marks are for the method. Marks are a guide to how much working an exam would expect. Questions written by Bloom Education in the style of GCSE (AQA, Edexcel, OCR) and Cambridge IGCSE papers.

A · Same number in front: add or subtract

  1. 1
    Solve x + y = 10 and x - y = 4.[3 marks]
    Show the answer

    x = 7, y = 3
    Add: 2x = 14.

  2. 2
    Solve 3a + b = 11 and a + b = 5.[3 marks]
    Show the answer

    a = 3, b = 2
    Subtract: 2a = 6.

  3. 3
    Solve 2x + 3y = 19 and 2x + y = 9.[3 marks]
    Show the answer

    x = 2, y = 5
    Subtract: 2y = 10.

  4. 4
    Solve 4p + q = 15 and 4p - 2q = 6.[3 marks]
    Show the answer

    p = 3, q = 3
    Subtract: 3q = 9.

  5. 5
    Solve 5m + 2n = 24 and 3m - 2n = 8.[3 marks]
    Show the answer

    m = 4, n = 2
    Add: 8m = 32.

B · Multiply first

  1. 6
    Solve 2x + y = 11 and x + 3y = 13.[4 marks]
    Show the answer

    x = 4, y = 3
    (1) × 3 - (2): 5x = 20.

  2. 7
    Solve 3x + 2y = 16 and x - y = 2.[4 marks]
    Show the answer

    x = 4, y = 2
    (2) × 2 + (1): 5x = 20.

  3. 8
    Solve 5a - 2b = 14 and 2a + b = 11.[4 marks]
    Show the answer

    a = 4, b = 3
    (2) × 2 + (1): 9a = 36.

  4. 9
    Solve 3x + 4y = 25 and 2x + 3y = 18.[4 marks]
    Show the answer

    x = 3, y = 4
    (1) × 2 - (2) × 3: -y = -4.

  5. 10
    Solve 5x - 3y = 1 and 2x + 5y = 19.[4 marks]
    Show the answer

    x = 2, y = 3
    (1) × 5 + (2) × 3: 31x = 62.

  6. 11
    Solve 4x + 3y = 5 and 3x - 2y = 8.[4 marks]
    Show the answer

    x = 2, y = -1
    (1) × 2 + (2) × 3: 17x = 34.

C · Substitution

  1. 12
    Solve y = 2x + 1 and 3x + y = 16.[3 marks]
    Show the answer

    x = 3, y = 7
    3x + 2x + 1 = 16, so 5x = 15.

  2. 13
    Solve x = 3y - 2 and 2x + y = 17.[3 marks]
    Show the answer

    x = 7, y = 3
    2(3y - 2) + y = 17, so 7y = 21.

  3. 14
    Solve 0.5x + y = 7 and x - y = 2.[3 marks]
    Show the answer

    x = 6, y = 4
    Add: 1.5x = 9.

D · Word problems

  1. 15
    Two adult and three child cinema tickets cost £36. One adult and two child tickets cost £21. Find the cost of each ticket.[4 marks]
    Show the answer

    Adult £9, child £6
    2a + 3c = 36, a + 2c = 21; (2) × 2 - (1): c = 6.

  2. 16
    A taxi charges a fixed fee plus a price per mile. A 5-mile journey costs £9.50 and an 8-mile journey costs £14. Find the fixed fee and the price per mile.[4 marks]
    Show the answer

    Fee £2, £1.50 a mile
    f + 5p = 9.5, f + 8p = 14; subtract: 3p = 4.5.

  3. 17
    A jar holds 25 coins, all 10p or 20p. Together they are worth £3.70. How many of each coin are there?[4 marks]
    Show the answer

    13 × 10p, 12 × 20p
    t + w = 25, 10t + 20w = 370; (1) × 10 and subtract: 10w = 120.

  4. 18
    Two numbers add up to 47. Their difference is 13. Find the two numbers.[4 marks]
    Show the answer

    30 and 17
    x + y = 47, x - y = 13; add: 2x = 60.

  5. 19
    Amara is three times as old as Ben. In 5 years' time she will be twice as old as him. How old are they now?[4 marks]
    Show the answer

    Ben 5, Amara 15
    a = 3b and a + 5 = 2(b + 5), so 3b + 5 = 2b + 10.

E · Line and curve (Higher)

  1. 20
    Solve y = x + 1 and y = x² - 1.[5 marks]
    Show the answer

    x = 2, y = 3 and x = -1, y = 0
    x² - 1 = x + 1, so x² - x - 2 = 0 = (x - 2)(x + 1).

  2. 21
    Solve x² + y² = 25 and y = x + 1.[5 marks]
    Show the answer

    x = 3, y = 4 and x = -4, y = -3
    x² + (x + 1)² = 25, so x² + x - 12 = 0 = (x + 4)(x - 3).

  3. 22
    Solve y = 2x - 3 and xy = 2.[5 marks]
    Show the answer

    x = 2, y = 1 and x = -0.5, y = -4
    x(2x - 3) = 2, so 2x² - 3x - 2 = 0 = (2x + 1)(x - 2).

  4. 23
    The lines y = 2x + 1 and y = 7 - x cross at the point P. Find the coordinates of P.[5 marks]
    Show the answer

    P = (2, 5)
    2x + 1 = 7 - x, so 3x = 6.

Before the exam

Simultaneous equations exam checklist

  • Label equations (1) and (2) to keep track.
  • Multiply every term in an equation to match the other.
  • Same sign? Subtract. Different signs? Add. Make sure you get the right one.
  • Find both unknowns and check in the other equation.
  • Quadratics give two pairs of answers, so check both.

Got stuck on a question?

Find the part of this guide it belongs to and go through the worked example again, line by line. Then put your answer back into the question: if it doesn't work, look for a sign or a step you skipped.

Cover of the Bloom simultaneous equations study guide
Free PDF: print it, work through it

All of this page as a 10-page guide, with every answer at the back. No sign-up.

Download the PDF (648 KB)

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