Free study guide · GCSE Foundation & Higher

Inequalities, solve them like equations, almost

Learn how to solve inequalities with step-by-step examples and exam-style questions with answers.

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Why does the inequality sign flip when you divide by a negative number?

Inequalities can feel tricky because they’re not just about numbers—they’re about balance. Think of them like a tipped see-saw. When you multiply or divide by a negative, the see-saw tips the other way, so you flip the inequality sign.

The picture to keep in your head: A tipped see-saw

An inequality is a see-saw that's tipped: 2x + 1 > 7 means the left side is heavier. Adding, subtracting, multiplying or dividing both sides by the same positive number keeps it tipped the same way. Multiplying or dividing by a negative number is like turning the see-saw round: the heavy side is now on the other side, so the sign flips. 5 > 2, but -5 < -2.

The method, every time

  1. Treat the inequality like an equation. Add or subtract the same number from both sides.
  2. Multiply or divide by a positive number. The see-saw stays tipped the same way.
  3. Divide by a negative number. Turn the see-saw round and flip the inequality sign.
  4. Sketch the number line. Use an open circle for < or >, a filled circle for ≤ or ≥.
  5. Check your answer. Substitute a value from the solution set into the original inequality.

Words you'll see

inequality
A mathematical statement showing one value is greater than or less than another.
flip
To change the direction of an inequality when multiplying or dividing by a negative.
interval
A range of values that satisfy an inequality, shown on a number line.
quadratic
An equation with a squared term, often solved by finding where it’s above or below zero.
boundary
The exact point where the inequality changes from true to false or vice versa.

Watch it explained

1 · Solving

Same steps as an equation

An inequality is like a tipped see-saw. The left side is heavier than the right side. To solve it, do the same to both sides, like balancing the see-saw. The answer is a range of values, not just one number. This is the same as solving an equation, but the result is a range, not a single value.

Worked exampleSolve 2x + 1 > 7
2x + 1 > 7
Start with the inequality
2x > 6
Subtract 1 from both sides
x > 3
Divide both sides by 2
x > 3
answer

Watch out

  • Writing x = 3. Use x > 3 to show the range
  • Losing the inequality sign halfway. Keep the inequality sign until the end
2 · The flip

Divide by a negative? Flip the sign

An inequality is like a tipped see-saw. When you divide by a negative number, the see-saw flips. This means the inequality sign must flip too. If you divide both sides by a negative number, always reverse the sign. You can avoid this by keeping the x terms positive.

Worked exampleSolve 5 - 3x ≤ 14
5 - 3x ≤ 14
Start with the inequality
-3x ≤ 9
Subtract 5 from both sides
x ≥ -3
Divide by -3, so flip the sign
x ≥ -3
answer

Watch out

  • Forgetting to flip the sign when dividing by a negative. Always flip the sign when dividing by a negative
  • Flipping the sign when adding or subtracting a negative. Only flip when multiplying or dividing by a negative
3 · Number lines and integers

Open circle, filled circle

An inequality is like a tipped see-saw. When you solve it, you find all the numbers that make it true. On a number line, open circles show numbers that are not included, like < or >. Filled circles show numbers that are included, like ≤ or ≥. For a double inequality, treat all three parts the same. List integer solutions carefully at the ends.

Worked exampleList the integers n such that -3 < 2n + 1 ≤ 7
-3 < 2n + 1 ≤ 7
Start with the double inequality
-4 < 2n ≤ 6
Subtract 1 from all three parts
-2 < n ≤ 3
Divide all three parts by 2
-1, 0, 1, 2, 3
-2 is not included (<), 3 is (≤)
-1, 0, 1, 2, 3
answer

Watch out

  • Including an end that isn't included. Check if the inequality is strict (< or >) before listing numbers
  • Doing a step to only two of the three parts. Apply the same step to all three parts of the double inequality
4 · Higher: quadratic inequalities

Find where the curve is above or below zero

The see-saw works for straight lines; with x2 you need a quick sketch. Solve the equation to find where the U-shaped curve crosses the x-axis: these are the critical values. Between them the curve dips below the axis, outside them it's above. So '< 0' gives one interval between the critical values, and '> 0' gives two parts outside them.

Worked exampleSolve x2 - x - 6 < 0
x2 - x - 6 < 0
Start with the inequality
(x - 3)(x + 2) = 0
Factorise to find the critical values
x = 3 or x = -2
Where the curve crosses the x-axis
-2 < x < 3
The U-shape is below the axis between them
x = 0: 0 - 0 - 6 = -6 < 0 ✓
Check with a value in the interval
-2 < x < 3
answer

Watch out

  • Square-rooting both sides of x2 > 9 and writing only x > 3. Remember to include both x > 3 and x < -3.
  • Giving the wrong region (inside instead of outside). Sketch the curve and test values to find where it is below or above zero.
Practice

20 exam-style inequalities questions

Show your working: most marks are for the method. Marks are a guide to how much working an exam would expect. Questions written by Bloom Education in the style of GCSE (AQA, Edexcel, OCR) and Cambridge IGCSE papers.

A · Solve

  1. 1
    Solve 2x + 3 > 7[2 marks]
    Show the answer

    x > 2
    2x + 3 > 7 → 2x > 4 → x > 2. The see-saw stays tipped because we subtracted 3 and divided by 2 (positive number).

  2. 2
    Solve 3x - 4 < 5[2 marks]
    Show the answer

    x < 3
    3x - 4 < 5 → 3x < 9 → x < 3. The see-saw stays tipped because we added 4 and divided by 3 (positive number).

  3. 3
    Solve 2(x + 1) > 6[2 marks]
    Show the answer

    x > 2
    2(x + 1) > 6 → x + 1 > 3 → x > 2. The see-saw stays tipped because we divided by 2 (positive number).

  4. 4
    Solve 4x + 1 < 3x + 5[2 marks]
    Show the answer

    x < 4
    4x + 1 < 3x + 5 → x + 1 < 5 → x < 4. The see-saw stays tipped because we subtracted 3x and 1 (positive numbers).

  5. 5
    Solve (2x + 1)/3 < 3[2 marks]
    Show the answer

    x < 4
    (2x + 1)/3 < 3 → 2x + 1 < 9 → 2x < 8 → x < 4. The see-saw stays tipped because we multiplied by 3 (positive number).

B · Negatives and flips

  1. 6
    Solve 7 - 2x > 1[2 marks]
    Show the answer

    x < 3
    Subtract 7: -2x > -6. Divide by -2 and flip: x < 3.

  2. 7
    Solve -4x ≥ 12[2 marks]
    Show the answer

    x ≤ -3
    Divide by -4 and flip the sign.

  3. 8
    Solve 3 - x < 8[2 marks]
    Show the answer

    x > -5
    Subtract 3: -x < 5. Multiply by -1 and flip: x > -5.

  4. 9
    Solve 2x + 9 ≤ 5x without dividing by a negative[2 marks]
    Show the answer

    x ≥ 3
    Subtract 2x from both sides: 9 ≤ 3x, so 3 ≤ x.

C · Integers and double inequalities

  1. 10
    List the integers x such that 1 < 2x - 1 ≤ 7.[3 marks]
    Show the answer

    2, 3, 4
    Add 1: 2 < 2x ≤ 8. Divide by 2: 1 < x ≤ 4.

  2. 11
    Find the largest integer x that satisfies 3x - 2 < 13.[3 marks]
    Show the answer

    4
    3x - 2 < 13. Add 2: 3x < 15. Divide by 3: x < 5. Largest integer less than 5 is 4.

  3. 12
    Find all integer solutions of 2 < 3x - 4 < 5.[3 marks]
    Show the answer

    No integer solutions
    Add 4: 6 < 3x < 9. Divide by 3: 2 < x < 3. No whole number lies strictly between 2 and 3.

  4. 13
    Find the smallest integer n such that 4n - 3 > 20.[3 marks]
    Show the answer

    6
    4n > 23, so n > 5.75; the smallest integer is 6.

D · Quadratic (Higher)

  1. 14
    Solve x2 < 16[3 marks]
    Show the answer

    -4 < x < 4
    x2 < 16 → x2 - 16 < 0 → (x - 4)(x + 4) < 0. The inequality holds when -4 < x < 4.

  2. 15
    Solve x2 - 5x + 4 ≥ 0[3 marks]
    Show the answer

    x ≤ 1 or x ≥ 4
    x2 - 5x + 4 = (x - 1)(x - 4). The inequality holds when x ≤ 1 or x ≥ 4.

  3. 16
    Solve x2 + 2x - 15 > 0[3 marks]
    Show the answer

    x < -5 or x > 3
    x2 + 2x - 15 = (x + 5)(x - 3). The inequality holds when x < -5 or x > 3.

  4. 17
    A rectangular garden has length (x + 5) m and width (x - 2) m. Find the values of x for which the area is greater than 30 m².[3 marks]
    Show the answer

    x > 5
    (x + 8)(x - 5) > 0 gives x < -8 or x > 5, but the width x - 2 must be positive, so x > 5.

E · Context

  1. 18
    A phone plan costs £10 per month plus £0.10 per text. A student has £15 per month. How many texts can they send?[3 marks]
    Show the answer

    at most 50 texts (x ≤ 50)
    Let x = number of texts. 10 + 0.10x ≤ 15. Subtract 10: 0.10x ≤ 5. Divide by 0.10: x ≤ 50.

  2. 19
    A taxi charges £3 plus £2 per mile. Jo has £20. What is the greatest whole number of miles she can travel?[3 marks]
    Show the answer

    8 miles
    3 + 2m ≤ 20, so 2m ≤ 17 and m ≤ 8.5; the greatest whole number is 8.

  3. 20
    A bus company charges £2 per ticket. A group of students has £60 to spend. How many tickets can they buy?[3 marks]
    Show the answer

    at most 30 tickets (x ≤ 30)
    Let x = number of tickets. 2x ≤ 60. Divide by 2: x ≤ 30.

Before the exam

Inequalities exam checklist

  • Treat it like an equation. Add or subtract the same number from both sides.
  • Flip the sign when multiplying or dividing by a negative. The see-saw tips the other way.
  • Use an open circle for < or >, a filled circle for ≤ or ≥. Show where the value lies.
  • Double inequalities: do all three parts. Solve for each part separately and find the overlap.
  • For quadratics: sketch the curve. Find where it’s above or below zero to solve the inequality.

Got stuck on a question?

Find the part of this guide it belongs to and go through the worked example again, line by line. Then put your answer back into the question: if it doesn't work, look for a sign or a step you skipped.

Cover of the Bloom inequalities study guide
Free PDF: print it, work through it

All of this page as a 10-page guide, with every answer at the back. No sign-up.

Download the PDF (621 KB)

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